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2n=3n^2+6n+12
We move all terms to the left:
2n-(3n^2+6n+12)=0
We get rid of parentheses
-3n^2+2n-6n-12=0
We add all the numbers together, and all the variables
-3n^2-4n-12=0
a = -3; b = -4; c = -12;
Δ = b2-4ac
Δ = -42-4·(-3)·(-12)
Δ = -128
Delta is less than zero, so there is no solution for the equation
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